y^2+12y+40=0

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Solution for y^2+12y+40=0 equation: 



y^2+12y+40=0

a = 1; b = 12; c = +40;
Δ = b2-4ac
Δ = 122-4·1·40
Δ = -16
Delta is less than zero, so there is no solution for the equation

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